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Use *, it will not be O(1) anymore def mul2(x, y) result = 0 for i in range(y) result = x return result Here, this function is O(y) the way we've defined it is dependent on the size of the input y, because we execute the for loop y times, and each time through the for loop we execute a constanttime operation 3> v l ô W Z W l l v X } X } u l } µ l P µ o } v l µ o z ( o v P l v v P l î ì í õ l^Z r } y r î ì í õ r ì ì ð X (X { x x y ~ w z} {ú x ~ z y w { } x y ~ x z x y x y { } ~ x z { ß Ä É Ð Â É Ó Û Å Ò â É Ô ÷ Ë Ï Ó È û ¦ ü ý þ ÿ ¢ Þ ½ £ Ì Ì â Ì Ì Ì Î Ï £ ¢ ½ Î Ó Â É È Ê Ì Ì Ë Í Ð â Î Ï Ó Ì É Î á Ì â Í Î Ó È ¦ × £ ¥ × ¡ × × × × ×

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This is asking me for all the values of (g o f)(x) = g(f(x)) for x = –3, –2, –1, 0, 1, 2, and 3So I'll just follow the points on the graphs and compute all the values (g o f)(–3) = g(f(–3)) = g(1) = –1I got this answer by looking at x = –3 on the f(x) graph, finding the corresponding yvalue of 1 on the f(x) graph, and using this answer as my new xvalue on the g(x) graphEkX = kEX if k is a constantB is easy just see where the line crosses the Y axis m (the Slope) needs some calculation m = Change in Y Change in X Knowing this we can work out the equation of a straight line

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